jis collage of engineering
kalyani 

TCS VISITED ON 22/04/05 
TEST WAS ONLINE.


VERBAL:- 10 SYNONYMS, 15 ANTONYMS,12 SENTENCE COMPLETION QUESTION. 

WHIMSICAL 
Approbation= 
Cacophony=disonent 
Virulent 
oscillating 
BOXUM=joly 
FUROR 
PRECARIOUS 
SERVILE 
REPUGNANCE 
EXONERATE 
MINION=dependent
CANDID=frank 
CENSURE= 
TENACIOUS 
ASSUAGE 
GRAMANE 
LUMINAR 
DEFLATION 
ECHELEON 
CONCILIATION=more friendly 
CONNOTATION =iner meaning 

1. In a two-dimensional array, X (9, 7), with each element occupying 
8 
bytes of memory, with the address of the first element X (1, 1) is 
3000, find 
the address of X (8, 5).

Soln:- The position of the target element from the start is ((8-1)
*7) + 
5 = 54.
       Hence, the starting addr of it is 3000 + (54-1)*8 = 3424 
[Since 
1st
       element's addr is already considered]

ans:-3424

2. In the word ORGANISATIONAL, if the first and second, third and 
forth, 
forth and fifth, fifth and sixth words are interchanged up to the 
last letter, 
what would be the tenth letter from right? Ans:-I R 
3. What is the largest prime number that can be stored in an 
8-bit,/6-bit/,9bit/,7,bit memory?

ans:-251 R 

4. Select the odd one out a. Oracle b. Linux c. Ingress d. DB2 
ans:-linux [All others are DBMS'] 

5. Select the odd one out a. WAP b. HTTP c. BAAN d. ARP 
ans:-BAAN [This not a protocol]

6 Select the odd one out a. LINUX b. UNIX c. SOLARIS d. SQL SEVER 
ans:- SQL SERVER [This a DBMS not an OS]

Revise such type of question these are very easy ,be cool , it's a 
very easy 
one, concern previous year question 

7 The size of a program is N. And the memory occupied by the program 
is 
given by M = square root of 4000N. If the size of the program is 
increased by 
1% then how much memory now occupied? 

Soln:- M1 = sqrt(S1) = sqrt(4000N)
       S2 = 101%S1 = 1.01N
       M2 = sqrt(S2) = sqrt(4000*(1.01N)) = sqrt(4040N)

       Though doing upto this is sufficient, you may go a bit further
       by calculating the % increase.

       %increase = (((sqrt(4040N) - sqrt(4000N)) / sqrt(4000N)) * 
100) 
%
                 = (((sqrt(40N) * (sqrt(101) - sqrt(100))) / (sqrt
(40N) 
* sqrt(100))) * 100) %
                 = (((sqrt(101) - 10) / 10) * 100) %
                 = ((10 * sqrt(101)) - 100) %
                 = ((10 * 10.05) - 100) %
                 = (100.5 - 100) %
                 = 0.5 %

8 In which of the system, decimal number 384 is equal to 1234? 
(data may be changed) 

Soln:- Let the system be of base n.
       So, n^3+(2*n^2)+(3*n)+4 = 384 [Try for some arbit values like 
5,6,7]

9 Number of faces, vertices and edges of a cube ans:-8,6,12 R 

10 Complete the series 10,11,12,17,---,26,22 

Soln:- There are actually two series here - 
       1> 10, 12, ..., 22 [diffs are 2, 4, 6, ...]
       2> 11, 17, 26 [diffs are 6, 9, ...]
       So the answer will be 16

11 Find the value of >>+25-++>16, where >denotes "square" and + 
denotes 
"square root". 

Soln:- >>+25-++>16 = (>(>(+(25)))) - (+(+(>(16))))
                   = (sqr(sqr(sqrt(25)))) - (sqrt(sqrt(sqr(16))))
                   = (sqr(25)) - (sqrt(16))
                   = 625 - 4 = 621

12 Find the result of the following __expression if, M denotes 
modulus 
operation, R denotes round-off, T denotes truncation: 
M(373,5)+R(3.4)+T(7.7)+R(5.8)

Soln:- M(373,5)+R(3.4)+T(7.7)+R(5.8) = 3 + 3 + 7 + 6 = 19

ans:-19

13 G(0)=-1, G(1)=1, G(N)=G(N-1) - G(N-2), G(5)= ?

Soln:- G(2) = G(1) - G(0) = 1 - (-1) = 2
       G(3) = G(2) - G(1) = 2 - 1 = 1
       G(4) = G(3) - G(2) = 1 - 2 = -1
       G(5) = G(4) - G(3) = (-1) - 1 = -2

ans:- -2

14 G(0)=1, G(1)=-1, G(N)=2*G(N-1) -3* G(N-2), G(5)= ?

Soln:- G(2)=2*G(1) -3* G(0) = 2*(-1) - 3*1 = -5
       G(3)=2*G(2) -3* G(1) = 2*(-5) - 3*(-1) = -7
       G(4)=2*G(3) -3* G(2) = 2*(-7) - 3*(-5) = 1
       G(5)=2*G(4) -3* G(3) = 2*1 - 3*(-7) = 23

ans:- 23

15 If TAFJHH is coded as RBEKGI then RBDJK can be coded as --------- 

Soln:-  T  A  F  J  H  H
        R  B  E  K  G  I
       -----------------
       -2 +1 -1 +1 -1 +1

       Hence,
        R  B  D  J  K
       -2 +1 -1 +1 -1
       --------------
        P  C  C  K  J

ans:-pcckj 

16 A power unit is there by the bank of the river of 900 meters 
width. 
A cable is made from power unit to power a plant opposite to that of 
the river 
and 3000mts away from the power unit. The cost of the cable below 
water is Rs. 
5/- per meter and cost of cable on the bank is Rs.4/- per meter. 
Find 
the total 
of laying the cable.

Soln:- Total cost under water = 900 * 5 = 4500 Rs
       Total cost on land = (3000 - 900) * 4 = 2100 * 4 = 8400 Rs
       Hence, total cost of laying = (4500 + 8400) = 12900 Rs

17 In calcutta, temperature at noon varies according to 

-t^2/6 + 12t + 12, where t is elapsed time from noon. Find how much 
temperature 
more or less in 3pm to 9pm

Soln:- at time 't' hrs from noon, temp in Cal = -t^2/6 + 12t + 12
       So, at 3 pm, temp = -3^2/6 + 12*3 + 12 = -1.5 + 36 + 12 = 46.5
       and, at 9 pm, temp = -9^2/6 + 12*9 + 12 = -13.5 + 108 + 12 = 
106.5

       Hence, at 9 pm, temp is (106.5 - 46.5) = 60 more than that at 
3 
pm.

18 The size of the bucket is N kb. The bucket fills at the rate of 
0.1 kb 
per millisecond. A programmer sends a program to receiver. There it 
waits for 
10 milliseconds. And response will be back to programmer in 20 
milliseconds. 
How much time the program takes to get a response back to the 
programmer, after 
it is sent? 
19 Which triangle is not possible ( degrees/sides are given) 
Ans:- 110/20/60( degree) (1,3,4) sides 

20 Which of the following are orthogonal pairs? a. 3i+2j b. i+j c. 
2i- 
3j 
d. -7i+j

Soln:- Here, for 3i+2j and 2i-3j are orthogonal.
       [Indication, constants swaped, sign changed]

20 Which of the following lines form orthogonal pairs hint:-m1*m2=-1 

21 If A, B and C are the mechanisms used separately to reduce the 
wastage of fuel by 30%, 20% and 10%. What will be the fuel economy 
if 
they were used 
combined.

Soln:- Using A, wastage reduces to, (100-30)=70%
       Using B, wastage reduces to, (70-(70*20%))=(70-14)=56%
       Using C, wastage reduces to, (56-(56*10%))=(56-5.6)=50.4%
Ans:- 51.4%

22. What is the power of 2/4/5? 

23 A, B and C are 8 bit no's. They are as follows: 
A 1 1 0 1 1 0 1 1 
B 0 1 1 1 1 0 1 0 
C 0 1 1 0 1 1 0 1 
Find ( (A-B) u C )=? 
Hint : 
A-B is {A}  {A n B}

Soln:-          A  1 1 0 1 1 0 1 1
                B  0 1 1 1 1 0 1 0
      ----------------------------
            A n B  0 1 0 1 1 0 1 0

                A  1 1 0 1 1 0 1 1
            A n B  0 1 0 1 1 0 1 0
      ----------------------------
            A - B  1 0 0 0 0 0 0 1

            A - B  1 0 0 0 0 0 0 1
                C  0 1 1 0 1 1 0 1
      ----------------------------
      (A - B) u C  1 1 1 0 1 1 0 1

ans:= 11101101 R 

24 A Flight takes off at 2 A.M from northeast direction and travels 
for 11 
hours to reach the destination which is in north west direction. 
Given the 
latitude and longitude of source and destination. Find the local 
time 
of 
destination when the flight reaches there? R 

25 A can copy 50 papers in 10 hours while both A & B can copy 70 
papers 
in 
10 hours. Then for how many hours required for B to copy 26 
papers

Soln:- A+B ----- 70 papers in 10 hrs
       A   ----- 50 papers in 10 hrs

   So,   B ----- 20 papers in 10 hrs
         B ----- 26 papers in (10/20)*26= 13 hrs


26 if a man A can do a work in 10 days and b can do the same work in 
15 days then find total wage given is 225 . find the wage of A. 

Soln:- In 1 day,
                A does 1/10th of the job
                B does 1/15th of the job

       So, the ratio of wages should be,
           A:B = (1/10): (1/15)
               = 15 : 10
               = 3 : 2

       Hence, the wage of A should be (3/5)*225 = 135

Ans:- 135

27 Find the singularity matrix from a given set of matrices?(Hint 
det(A)==0) 2*2 order


(Momentum*Velocity)/(Acceleration * distance ) find units.

Soln:- (Momentum*Velocity)/(Acceleration * distance )
       = (([MASS]*[DISTANCE]/[TIME])*([DISTANCE]/[TIME]))
         / (([DISTANCE]/([TIME]*[TIME]))*[DISTANCE])

       = (([MASS]*[DISTANCE]*[DISTANCE])/([TIME]*[TIME]))
         / (([DISTANCE]*[DISTANCE])/([TIME]*[TIME]))

       = [MASS]

Ans:- Unit is of mass, say, kg


28 (Power * time)/( velocity*velocity)= what.

29 (Energy * time * time)/(mass * distance) = what 
30 

49. Which of the following set of numbers has the highest Standard 
deviation? 
1,0,1,0,1,0 
-1,-1,-1,-1,-1,-1 
1,1,1,1,1,1 
1,1,0,-1,0,-1
hint:- 1 may be replaced by 7 

Soln:- Vague approach-> diff between two extremes is most for the
                        last set. so, it's SD is max.
                        [Correct ans]

50. Match the following: 
1. Male - Boy ---> a. A type of 
2. Square - Polygon ---> b. A part of 
3. Roof - Building ---> c. Not a type of 
4. Mushroom - Vegetables ---> d. A superset of 
Ans: 1- d, 2- a, 3- b, 4- c R 

51. Match the following. 
1. brother  sister ---> a. Part of 
2. Alsatian  dog ---> b. Sibling 
3. sentence  paragraph ---> c. Type of 
4. car - steering ---> d. Not a type of 
Ans. 1-b, 2-c, 3-a, 4-d 

hint:- do all previous year question . most of the question are of 
same type. 
There is great difference between previous year vocab and this year. 
Go 
through (barron's). 

critical reasioning question were puzzle's (3) . linear arrangement 
,grouping,relation,directional. 
Go through GRE. 
